Arectangular athletic field is twice as long as it is wide. if the perimeter of the athletic field is 270 yards, what are its dimensions?

The perimeter (P) of any rectangular figure is calculated through the formula,
                                        P = 2L + 2W
where L and W are length and width, respectively. With the condition that length should be twice the width, it may be expressed as L = 2W. Substituting the given values,
                                          270 yards = 2(2W) + 2W
Solving for W gives W = 45. From this, L is equal to 90. Thus, the dimensions are W = 45 yards and L = 90 yards.