Given a parallelogram ABCD, with AD = AB. The bisector of angle A intersects BC at G, and the bisector of angle B intersects AD at H. Prove that ABGH is a rhombus.

Me write an equation for the interior angles of this triangle that uses the triangle sum theorem

Select the conic section that represents the equation. 3x2 + 3y2 -2x + 4 = 0

Which is a logical conclusion based on the given information? a. figure abcd is a rhombus by the definition of a rhombus. b. segment ac is congruent to segment dc by cpctc. c. angle acb is congruent to angle adc by the angle-side-angle theorem. d. triangle acd is congruent to triangle cab by the hypotenuse-leg theorem.