Mathematics, 26.02.2020 23:34, Jake10383

Can someone please answer this question please show work and please answer it correctly please

Answers: 2

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answered: robinsonchristopher0

answer:

Problem 3

Part A: Distribute and Combine like terms

3(2x - 10y) + 15y - 6(3x - 8y)

6x - 30y + 15y - 18x + 48y

-12x + 33y

Part B: Factor the expression -> -12x + 33y

-12x + 33y

-3(4x - 11y)

Problem 4

Find if the table is proportional

In order to be proportional, the amount earned / number of lawns need to equal 15.

1/15 = 15

2/30 = 15

3/48 = 16

4/64 = 16

No, this table is not proportional because the first two times the lawn is mowed, that person earns $15, but the next two times that person earns $16. Therefore, it is a not proportional table.

answered: goldenrizo

answer:

No because if it were proportional the values would be multiples of 15.

Step-by-step explanation:

Proportional relationships are constant and are multiplied by the same number always. In this case it should be 15 being continuous. While at the first two lawns it would seem that this relationship is proportional you then get to the third lawn where it is 48 (when it should be 45 if this were proportional).

To often check proportional relationships you divide the original number (15 in this case) by the other number (other cases money was earned) and see if they equate to the amount of lawns mowed. Therefore if you did 48/15 it would NOT equal 3 (the amount of lawns mowed by then), therefore not proportional.

answered: Guest

hard

step-by-step explanation:

Outline the necessary transformations to prove cbf ≅ edf using a paragraph proof. be sure to name

answered: Guest

answer:

total cost for tiles and paints is $924.

step-by-step explanation:

we have been given that a community hall is in the shape of a cuboid. the hall is 40m long 15m high and 3m wide.

the paint will be required for 4 walls and ceiling.

let us find area of walls and ceiling.

$\text{area of walls and ceiling}=(2*40*15)+(2*3*15)+(40*3)$

$\text{area of walls and ceiling}=1200+90+120$

$\text{area of walls and ceiling}=1410$

therefore, the area of walls and ceiling is 1410 square meters.

given: cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. therefore,

$\text{ the total painting cost}=10*(\frac{1410}{25})$

$\text{ the total painting cost}=10*56.4=564$

therefore, the total painting cost is $564.

tiles will be required for floor. let us find the area of floor.

$\text{area of floor} = 40*3\text{ square meters}$

$\text{area of floor} =120\text{ square meters}$

given: 1m squared floor tiles costs $3. so,

$\text{total cost for tiles} = 3*120 = 360$

therefore, the total tiles cost is $360.

now let us find combined total cost of tiles and paint.

$\text{combined total cost}= 564+360 = 924$

therefore, the combined total cost of tiles and paint is $924.

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