The circumference of the inner circle is 66 ft. The distance between the inner circle and the outer circle is 44 ft. By how many feet is the circumference of outer circle greater than the circumference of the inner circle? Use 22/7 for PI.

  276 4/7 ft

Step-by-step explanation:

Let r1 represent the radius of the inner circle. Then its circumference in feet is ...

  C = 2πr

  66 = 2π(r1)

If the radius of the outer circle is (r1 +44), then its circumference is ...

  C = 2π(r1 +44) = 2π(r1) +2π(44)

  C = 66 +88π

Then the difference in the circumferences is ...

  (66 +88π) - (66) = 88π

Using the given value of π, the difference in circumferences is ...

  (88 ft)(22/7) = 1936/7 ft = 276 4/7 ft

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x