The height in feet of a bottle rocket is given by h(t) = 160t - 16t where t is the time in seconds how long will it take for the rocket to return to the ground. What is the height after 2 seconds

a.) t = 16 seconds

b.) h(2) = 256 feet.

Step-by-step explanation:

a.)Bottle rocket height in feet is given by h(t)  = 160t - 16.

When the rocket returns to the ground its height will be zero.

Therefore we can write the equation above as  

 160t - 16 = 0

⇒16t ( 16 - t) = 0

On solving the equation above we get two values for t which are

t = 0 seconds  and t = 16 seconds.

We ignore t = 0 seconds because this is the starting time.

Therefore we can say that the rocket returns to the ground at time t = 16 seconds.

b.) The height in feet after 2 seconds will be given by

  h(2 seconds)  = (160 ×2)  -  (16 × ) = 320 - 64  = 256 feet.

vertical=18cm horizontal=18cm hypotenuse=25.5

step-by-step explanation:

8.3 and the 3 is repeating

hope this .