Paul, who is self employed, placed $30,000 in an account that pays 6% annual interest, compounded quarterly. How much interest was earned in 10 years?

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1+r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

From the information given,

P = 30000

r = 6% = 6/100 = 0.06

n = 4 because it was compounded 4 times in a year.

t = 10 years

Therefore,.

A = 30000(1 + 0.06/4)^4 × 10

A = 30000(1 + 0.015)^40

A = 30000(1.015)^40

A = $54421

The amount of interest earned after 10 years is

54421 - 30000 = $24421

32

step-by-step explanation:

let f (x ) is a function and c be a positive real number,   the graph of the function g (x ) = f (cx ) is represented as follows.

when, c > 1,   the function compresses it in the x - direction.

when, 0 < c < 1, the function stretches it.

the function is g ( x ) = (9x )2.

the heighest power of x in g ( x ) = (9x )2 is 2, so the parent function is square function.

the equation of parent function is f ( x ) = x 2 .

the function is g ( x ) = (9x )2 and the parent function is f ( x ) = x 2 .

so, the functions f and g have the following relationship.

g ( x ) = f ( 9x ).

compare the function g ( x ) = f ( 9x ) with g (x ) = f (cx ).

c = 9 ( > 1 ).

so, the function g (x ) = (9x )2 compresses it in the x - direction.

step-by-step explanation: