The proof that ΔEFG ≅ ΔJHG is shown.

Given: G is the midpoint of HF, EF ∥ HJ, and EF ≅ HJ.

Prove: ΔEFG ≅ ΔJHG

Triangles E F G and J H G share common point G.

Statement

Reason

1. G is the midpoint of HF 1. given

2. FG ≅ HG 2. def. of midpoint

3. EF ∥ HJ 3. given

4. ? 4. alt. int. angles are congruent

5. EF ≅ HJ 5. given

6. ΔEFG ≅ ΔJHG 6. SAS

What is the missing statement in the proof?

∠FEG ≅ ∠HJG

∠GFE ≅ ∠GHJ

∠EGF ≅ ∠JGH

∠GEF ≅ ∠JHG

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value

answer: i feel you honey.

step-by-step explanation:

30.5*10=350$

you have to multiply the number without the decimal point then add it later but if its tenn u must move the place value of the decimal point 1 to the right.