What is the measure of angle CED

Option D:

p, because ∠ABC ∠EDC.

Solution:

In ΔABC and ΔDCE,

Vertically opposite angles are congruent.

∠ACB ≅ ∠DCE

∠ABC ≅ ∠EDC

we cannot proceed further,

So ΔABC and ΔDC are not congruent triangles.

By this, Option A, Option B and Option C are false.

In ΔABC and ΔEDC,

Vertically opposite angles are congruent.

∠ACB ≅ ∠DCE (Angle)

∠ABC ≅ ∠EDC (Angle)

By AA similarity ΔACB and ΔDCE similar triangles.

Corresponding parts of similar triangles are congruent.

∠CED = ∠BAC

∠CED = p

Hence option D is the correct answer.

p, because ∠ABC ∠EDC.

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.