During the 2012-2013 NBA season, Jamal Crawford playing for the Los Angeles Clippers, had a free throw percentage of 0.871. Using complete sentences, describe the likelihood that he would make the free throw each time he stepped up to the line that season. Explain your reasoning.

Xis -1/2
y is 35/4.

One shot. if 60% of 10 is 6, then what is 70%? we know it would be seven (since 60% is mathematically 60/100, or 6/10, then 70% is 70/100, or 7/10) but we can check anyway using ratios: 6 : 60% = x : 70%*inverse multiplicationx * 60% = 6 * 70%*divide both sides by 60%x = (6 * 70%) / 60%x = 7and since he has made 6 shots already, he would need just one more to get 7 shots or 70%. if the explanation is too confusing, comment and i will try to