Let f={(-2,4),(-1,2)(0,0)(1,-2),(2,5)}. let g ={(-33),(-1,1),(0,-3)(1,-4)(3,-6)}. What is g(f(2))?

g(f(2)) does not exist if

g={(-3,3),(-1,1),(0,-3),(1,-4),(3,-6)} and f={(-2,4),(-1,2),(0,0),(1,-2),(2,5)}.

Step-by-step explanation:

Hi. Welcome to .

When finding g(f(2)), you must compute f(2) first.

Looking at f={(-2,4),(-1,2),(0,0),(1,-2),(2,5)}, we see that the ordered pair (2,5) is contained within the set defined as the set f. This means f(2)=5.

So now we have g(f(2))=g(5).

We now need to look at our set named g, g={(-3,3),(-1,1),(0,-3),(1,-4),(3,-6)}. We see the the no ordered pair looks like (5,something). The only conclusion is that g(f(2)) does not exist.

answer: ask

step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°