Thanks to its environmental initiatives, Lexington has cut its annual CO2 emissions by 5%. This year, the town produced 380,000 metric tons of emissions. If the downward trend continues, how much CO2 will be produced 3 years from now?

If necessary, round your answer to the nearest whole number.

Step-by-step explanation:

If the downward trend continues, it means that the CO2 production will keep on decreasing exponentially by 5%. We would apply the formula for exponential depreciation which is expressed as

A = P(1 - r)^t

Where

A represents the amount of CO2 produced after t years.

t represents the number of years.

P represents the initial amount of CO2 produced.

r represents rate at which its production is reducing.

From the information given,

P = 380000

r = 5% = 5/100 = 0.05

t = 3

Therefore

A = 380000(1 - 0.05)^3

A = 380000(0.95)^3

A= 325803 metric tons of emissions.

answer: 8 years

step-by-step explanation:

the explanation is that in 8 years the child will be 20 and in 8 years the father will be 40 and 20 is half of 40.

asnwer is (g o h o f)(x) = 2x - 6/x + 7

step-by-step explanation:

given,

f(x) = x - 3/x

g(x) = x + 3

h(x) = 2x + 1

we need to find : (g o h o f)(x)

we can write (g o h o f)(x) = g[ h{ f(x) } ]

so first we find h{f(x)}

h{f(x)} = f(x) + 3 = (x - 3/x) + 3

h{f(x)} = x - 3/x + 3

now we find g[ h{ f(x) } ].

g[ h{ f(x) } ] = g(x - 3/x + 3)       {plug h{f(x)} = x - 3/x + 3 in g[h{f(x)}] }

g(x - 3/x + 3) = 2 (x - 3/x + 3) + 1

                    = 2x - 6/x + 6 + 1

                    = 2x - 6/x + 7

hence we get (g o h o f)(x) = 2x - 6/x + 7