The perimeter of rectangle ABCD is four times greater than the perimeter of rectangle EFGH.

What is the perimeter of ABCD?

*Perimeter = 2L + 2W*

4x2−x+12

4x2−x+16

8x2−2x+24

16x2−4x+48

16x2−12x+48

4x2−3x+12

The answer to your question is 8x² - 2x + 24

Step-by-step explanation:

Data

EF = x² - x + 6

GF = x² + 1/2x

Perimeter

P = 2L + "W

But the condition is that the perimeter of rectangle ABCD is twice the perimeter of rectangle EFGH so.

Perimeter of EFGH = 4L + 4W

Substitution

Perimeter = 4(x² - x + 6) + 4(x² + 1/2x)

Simplification

Perimeter = 4x² - 4x + 24 + 4x² + 2x

                 = 8x² - 2x + 24

no problobm

step-by-step explanation:

answer is 8x+24

area of vanessa's patio = length × width

given, length = (3x² + 5x + 10)

width = (x² - 3x - 1)

area of vanessa's patio = (3x² + 5x + 10)(x² - 3x - 1)

= 3x²(x² - 3x - 1) + 5x(x² - 3x - 1) + 10(x² - 3x - 1)

= 3x⁴ - 9x³ - 3x² + 5x³ - 15x² - 5x + 10x² - 30x - 10

= 3x⁴ - 4x³ - 8x² - 35x - 10

hence, expression of vanessa's patio = (3x⁴ - 4x³ - 8x² - 35x - 10)