Dr. Miriam Johnson has been teaching accounting for over 20 years. From her experience she knows that 60% of her students do homework regularly. Moreover, 95% of the students who do their homework regularly generally pass the course. She also knows that 85% of her students pass the course. Let event A be Do homework regularlyand B be Pass the course. a.What is the probability that a student will do homework regularly and also pass the course? (Round your answer to 2 decimal places.)b. What is the probability that a student will neither do homework regularly nor will pass the course?(Round your answer to 2 decimal places.)

a.) 0.57

b.)  0.12

Step-by-step explanation:

Let the event that students do homework regularly  be the event A

It is given that the probability that students do homework regularly , p(A)= 0.6

Let the event that students pass the course  be the event B.

It is given that the probability that students pass the course, p(B) = 0.85

It is also given that students who  do their homework  also pass the course with a probability of 0.95.

Therefore p( B | A) =0.95

a.) The probability that a student will do the homework regularly and also pass the course

       ∴ p(B | A) × p(A)  = 0.95 × 0.6 = 0.57

b.)  

Therefore

.19875994384

step-by-step explanation:

1699/ 8548

7.25

step-by-step explanation:

we know that 7 equals to 7.0. we also know that 1/4=0.25. so we can add the two together and we get 7.25