Water leaves a fireman’s hose (held near the ground) with an initial velocity v0 = 17 m/s at an angle θ = 25.5° above horizontal. Assume the water acts as a projectile that moves without air resistance. Use a Cartesian coordinate system with the origin at the hose nozzle position.

Step-by-step explanation:

Projectile motion is a form of motion in which an object or particle (called a projectile) is thrown

near the earth's surface, and it moves along a curved path under the action of gravity only.

In projectile motion, the horizontal motion and the vertical motion are independent of each

other; that is, neither motion affects the other.

The horizontal component of the velocity of the object remains unchanged throughout the

motion. The vertical component of the velocity increases linearly, because the acceleration due to

gravity is constant (g=9.81 m/s2

).

= 0 cos

0 = 0 sin

To find the time of flight, determine the time the projectile takes to reach maximum height.

The time of flight is just double the maximum-height time.

Start with the equation:

= 0 + = 0 −

At maximum height,

= 0

The time to reach maximum height is

=

0

=

0 sin

=

17.5 sin 31.5°

9.81 = 0.9321

Horizontal distance, = 0

=

0 cos 0 sin

=

0

2

sin 2

2

=

17.5

2

sin(2 ∗ 31.5°)

2 ∗ 9.81 = 13.91

=

0 sin

; =

0

2

sin 2

2�

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation: