A skyrocket firework burns fuel as it climbs. Its mass, m(h) kg, at height h m is given by m(h)=0.96+ 0.065 1+h . m(h)=0.96+0.0651+h.(a) What is the mass of the rocket at h = 0 just before it is launched?(b) Show that the mass decreases as the rocket climbs.(c) What work would be required to lift the rocket 10 m if its mass did not decrease?(d) Approximate the work done as the rocket goes from height h to h + ?h.(e) The rocket explodes at h = 250 m. Find total work done by the rocket from launch to explosion

6 hours 48 min

step-by-step explanation:

68÷5=13.6

13.6×30=408min=6 hours 48 min.

hope to and hope that my answer is brainliest.(follow me )

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

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mrb

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there is no points to select.

step-by-step explanation: