Pls help geo/ trig

Kayson is looking at two buildings, building A and building B, at an angle of elevation of 59°. Building A is 40 feet away, and building B is 60 feet away. Which building is taller and by approximately how many feet?

Building A; it is around 66.57 feet taller than building B
Building A; it is around 33.29 feet taller than building B
Building B; it is around 66.57 feet taller than building A
Building B; it is around 33.29 feet taller than building A

Solution:

Kayson is looking at two buildings, building A and building B, at an angle of elevation of 59°

Building A is 40 feet away, and building B is 60 feet away

This forms a right angled triangle

height of building is the perpendicular

Distance between kayson and building forms the base ( adjacent)

If the height of the building A is x feet, then

Thus, height of building A is 66.57 feet

Building B is 60 feet away

If the height of building is y feet,

Thus, building B is taller

Building B - building A = 99.86 - 66.57 = 33.29 feet

Thus building B is taller and it is around 33.29 feet taller than building A

addition

step-by-step explanation:

2.2°  

step-by-step explanation:

let θ = the angle of elevation.

tanθ =77/2020

tanθ = 0.038 12

      θ = tan⁻¹0.038 12

      θ = 2.2°