Graph
f
(
x
)
=
x
2
−
10
x
+
24
f(x)=x2-10x+24.

F(x)=x^2 - 10x + 24 = (x - 4)(x - 6) i.e. f(x) crosses the x-axis at x = 4 and x = 6.
f(x) written in vertex form is (x - 5)^2 -1 meaning that the vertex is (5, -1)
Therefore, the graph of f(x) is a parabola facing up with vertex at (5, -1) and x-intercepts at x = 4 and x= 6.

Ithink the answer would be knew