A machinist has to manufacture a circular metal disk with area 1060π sq. cms. How close to the exact radius must the machinist control the radius if he is allowed an error tolerance of ±20π sq. cms. in the area of disk?

The radius of the disk must be close to 33cm

Step-by-step explanation:

Formula for calculating the area of a circular metal disk is Πr² since area of a circle is Πr². If the area of the disk is 1060π sq. cms, to get the radius of the disc, we will use the formula;

A = Πr² where;

A is the area of the disc

r is the radius of the disc

Given A = 1060π sq. cms

1060Π = Πr²

1060 = r²

r = √1060

r = 32.56cm approximately

If he is allowed a tolerance of ±20Πsq. cms in area, this means that we can use 1060±20Πsq. cms as the area which is equivalent to either 1080sq. cms or 1040sq. cms

If A = 1080sq. cms

r = √1080 = 32.86cm

If A = 1040sq. cms

r = √1040 = 32.25cm

If the values of the radius are compared, the radius of the metal disk must be close to 33cm approximately which are within the tolerance limit of the area.

what are the things "represented below"?

step-by-step explanation:

nobody can if you dont give the choices

each side has a different length.  

step-by-step explanation: