Example: Consider an experiment that selects a cell phone camera and records the recycle time of a flash (the time taken to ready the camera for another flash). The possible values for this time depends on the resolution of the timer and on the minimum and maximum recycle times. If it is known that all recycle times are between 1.5 and 5 seconds, show the sample space.

Step-by-step explanation:

1)

S = {1<=x<=10}

where x = the recycle time.

2)

E1 = {1.5<=x<=5}

3)

E2 = {2<=x<=8}

4)

E1 U E2 = {1.5<=x<=8}

5)

E1 and E2 = {2<=x<=5}

6)

E1' = {1<=x<1.5} U {5<x<=10}

7)

E2' = {1<=x<2} U {8<x<=10}

Thus,

E1 U E2' = {1<=x<5} U {8<x<=10} [ANSWER]

the 8 in 8,420 is in the thousands place so it's value is 8 thousand.

the 8 in 6,870 is in the hundreds place so it's value is 8 hundred.

divide 8000 by 800 to find the answer:

8000 / 800 = 10

the 8 in 8,420 is 10 times greater than the 8 in 6,870

no

step-by-step explanation: