p Ă· r = tan(x)
step-by-step explanation:
given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.
graph is missing so i will create the graph as per given information.
the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.
now we need to find about what is p Ă· r equal to.
so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p Ă· r, because p is the altitude and r is the base.
![\tan\left(x\right)=\frac{\left[altitude\right]}{\left[base\right]}=\frac{p}{r}](/tex.php?f=\tan\left(x\right)=\frac{\left[altitude\right]}{\left[base\right]}=\frac{p}{r})
=\frac{p}{r})
)
p Ă· r=tan(x)
hence final answer is p Ă· r=tan(x).
