In a certain community, 36 percent of the families own a dog and 22 percent of the families that own a dog also own a cat. In addition, 30 percent of the families own a cat. What is(a) the probability that a randomly selected family owns both a dog and a cat?

0.0792

Step-by-step explanation:

the probability that a family owns a dog= P(D)=36%=0.36

the probability that a family owns a dog also owns a cat=P(CnD)=22%=0.22

the probability that a family owns a cat =P(C)=30%=0.3

therefore, Probability that a randomly selected family owns both a dog and cat is given as

P(C∪D) = P(C∩D)×P(D)

=0.22×0.36

=0.0792

≈0.08

i want to die

what the hell man, i just want the points lol

the answer is 844

step-by-step explanation:

it is 844 because if you add 836.50 + 7.5 you will get 844