Mathematics, 25.02.2020 02:27, YatesDevon3214
A small town has 2000 inhabitants. At 8 AM, 160 people have heard a rumor. By noon half the town has heard it. At what time will 90% of the population have heard the rumor? (Do not round k in your calculation. Round your final answer to one decimal place.)
Answers: 1
![y(t) = \frac{y_{o}}{[y_{o} + (1 + y_{o})e^{-kt}]}](/tpl/images/0522/4909/43245.png)
![\frac{1}{2} = \frac{0.08}{[0.08 + (1 - 0.08)e^{-4k}]}](/tpl/images/0522/4909/ada19.png)
![\frac{0.08}{[0.08 + 0.92e^{-4k}]} = \frac{1}{2}](/tpl/images/0522/4909/b3693.png)
![\frac{0.08}{[0.08 + 0.92e^{-0.06106t}]} =0.9](/tpl/images/0522/4909/443fd.png)
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A small town has 2000 inhabitants. At 8 AM, 160 people have heard a rumor. By noon half the town has...
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