Product specifications call for a part at Vaidy Jayaraman's Metalworks to have a length of 1.200 " plus or minus . 070 ". Currently, the process is performing at a grand average of 1.200" with a standard deviation of 0.010". Calculate the capability index of this process. The Upper C Subscript pk of this process is nothing (round your response to two decimal places).

Step-by-step explanation:

Upper specification limit (USL) = 1.200+0.070 = 1.270

Lower specification limit (LSL) = 1.200-0.070 = 1.130

Mean = 1.200

Standard deviation (SD) = 0.010

Cpl = (Mean - LSL) / (3 x SD) = (1.200-1.130)/(3x0.010) = 0.070/0.03 = 2.33

Cpu = (USL - Mean) / (3 x SD) = (1.270-1.200)/(3x0.010) = 0.070/0.03 = 2.33

Process capability index (Cpk) = Minimum of (Cpu, Cpl)

= Minimum of (2.33, 2.33)

= 2.33

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet