Mathematics, 24.02.2020 18:56, Sl33pyGrl
What else would need to be congruent to show that AABC= AXYZ by ASA?
Given:
/ Xã A
O A. 27= LA
O B. AC = x2
O
C. BC=YZ
O D. ZY=20
Answers: 2
Mathematics, 20.06.2019 18:04, Uc34758
Here is their argument. given the obtuse angle x, we make a quadrilateral abcd with ∠dab = x, and ∠abc = 90◦, and ad = bc. say the perpendicular bisector to dc meets the perpendicular bisector to ab at p. then pa = pb and pc = pd. so the triangles pad and pbc have equal sides and are congruent. thus ∠pad = ∠pbc. but pab is isosceles, hence ∠pab = ∠pba. subtracting, gives x = ∠pad−∠pab = ∠pbc −∠pba = 90◦. this is a preposterous conclusion – just where is the mistake in the "proof" and why does the argument break down there?
Answers: 2
Mathematics, 21.06.2019 17:30, Lovergirl13
Apositive number a or the same number a increased by 50% and then decreased by 50% of the result?
Answers: 3
What else would need to be congruent to show that AABC= AXYZ by ASA?
Given:
/ Xã A
...
Given:
/ Xã A
...
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