A ball is tossed up vertically from ground level and returns to earth 6 s later. What was the initial velocity of the ball and how high did it go?

initial velocity = 29.4m/s

maximum height = 44.1m

Step-by-step explanation:

This problem is a projectile motion. The ball is tossed vertically from the ground, which means the angle between the ball and the horizontal is 90°

° (the ball is tossed vertically)

2Usinα = g*T

2U =gT/sinα

2U = 9.8* 6/ sin90°

2U=58.8

U = 58.8/2 =29.4

U=29.4m/s

maximum height attained (H) =

=

maximum height =44.1m

answer: it's a

step-by-step explanation:

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.