Mathematics, 24.02.2020 16:58, kenziebug34

Which expressions are completely factored? Select each correct answer. 18y^3−6y=3y(6y^2−2) 32y^10−24=8(4y^10−3) 20y^7+10y^2=5y(4y^6+2y) 16y^5+12y^3=4y^3(4y^2+3)

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answered: 1r32tgy5hk7

The expressions that completely factored are:

$32y^{10}-24$ = 8( $y^{10}-3$ ) ⇒ 2nd

$16y^{5}+12y^{3}=4y^{3}(4y^{2}+3)$ ⇒ 4th

Step-by-step explanation:

Complete factorization means the terms in the bracket has no common factor

∵ The expression is 18y³ - 6y

- Find the greatest common factor of the numbers and the variable

∵ The greatest common factor of 18 and 6 is 6

∵ The greatest common factor of y³ and y is y

∴ The greatest common factor is 6y

- Divide each term by 6y to find the terms in the bracket

∴ 18y³ - 6y = 6y(3y² - 1) ⇒ not the same with the answer

∵ The expression is $32y^{10}-24$

∵ The greatest common factor of 32 and 24 is 8

∴ The greatest common factor is 8

- Divide each term by 8 to find the terms in the bracket

∴ $32y^{10}-24$ = 8( $y^{10}-3$ ) ⇒ the same with the answer

∴ The expression $32y^{10}-24$ = 8( $y^{10}-3$ ) is completely factored

∵ The expression is $20y^{7}+10y^{2}$

∵ The greatest common factor of 20 and 10 is 10

∵ The greatest common factor of $y^{7}$ and y² is y²

∴ The greatest common factor is 10y²

- Divide each term by 10y² to find the terms in the bracket

∴ $20y^{7}+10y^{2}=10y^{2}(2y^{5}+1)$ ⇒ not the same with the answer

∵ The expression is $16y^{5}+12y^{3}$

∵ The greatest common factor of 16 and 12 is 4

∵ The greatest common factor of $y^{5}$ and y³ is y³

∴ The greatest common factor is 4y³

- Divide each term by 4y³ to find the terms in the bracket

∴ $16y^{5}+12y^{3}=4y^{3}(4y^{2}+3)$ ⇒ the same with the answer

∴ The expression $16y^{5}+12y^{3}=4y^{3}(4y^{2}+3)$ is completely factored

The expressions that completely factored are:

$32y^{10}-24$ = 8( $y^{10}-3$ )

$16y^{5}+12y^{3}=4y^{3}(4y^{2}+3)$

answered: Guest

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

For the figures below, assume they are made of semicircles, quarter circles and squares. for each sh

answered: Guest

Answer

1 number

explanation

if we use a graphing calculator, there is only one such number $c\in[0.5,0.75]$ that satisfies the conclusion of the mean value theorem, that is, a number $c\in[0.5,0.75]$ such that

$f'(c) = \dfrac{f(0.75) - f(0.5)}{0.75-0.5},$

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.