Farmer Ed has 600 meters of fencing, and wants to enclose a rectangular plot that borders on a river. If Farmer Ed does not fence the side along the river, find the length and width of the plot that will maximize the area. What is the largest area that can be enclosed?

The plot must have x=150 m y=300 m and its maximum area is

Step-by-step explanation:

Maximum Values of Functions

Let f(x) be a real function and f'(x) its derivative. The values for which f'(x)=0 are called the critical points. If x=a is a critical point of f(x) and

f''(a)>0, then x=a is a minimum

f''(a)<0, then x=a is a maximum

The question requires us to maximize the area of the rectangular plot, knowing the perimeter of the fencing is 600 m.

The perimeter of a rectangle of sides x and y is

Since the side along the river (assumed to be y) won't be fenced, then the perimeter of the fence is

Solving for y

Now, the area of the rectangle is

Using the relation found above:

Find the derivative

Equal to zero

Solve for x

Find the second derivative

Since it's negative, the value x=150 is a maximum

The value of y is

Thus, the dimensions of the plot are x=150 m, y=300 m

And the maximum area of the plot is

step-by-step explanation:

the answer is 89 d

i took the test

soo this can be solve by using the formula:

f = p( 1 + i)^ n

where f is the future profit

p is the initial profit

i is the percent increase

n is the number of years

a . f = 30000 ( 1.05)^n

b. f = 30000 ( 1.05)^15

f = $62,368