Suppose that you have 9 cards. 4 are red and 5 are purple. The cards are well shuffled. You randomly draw two cards without replacement.
• R1 = first card drawn is red
• R2 = second card drawn is red

P(R1 AND R2) = Round your answer to two decimal places.
P(At least one red) = Round your answer to two decimal places.
P(R2|R1) = Round your answer to two decimal places.
Are R1 and R2 independent?

P(R1 AND R2) 1/6 = 0.17

P(At least one red)=5/6=0.83

R2/R1=1/6=0.84

Are R1 $ R2 independent? No

Step-by-step explanation: as card drawn was not replaced, when R1 was drawn, total no of cards reduced to 8, and number of red reduced to 3

A) 4/9×3/8

=1/6= 0.17

B)The probability of at least one green is

P(at least one green) = 1 - P(no green)

P(no green) = 4/9*3/8 = 12/72 = 1/6

Thus P(at least one green) = 1 - 1/6 = 5/6= 0.83

C) R2/R1= 3/8÷4/9

=0.84

D)R1 and R2 are not independent because the cards are not replaced.

javeir earned 56 dollors more than kyle so kyle and javier had 14w but javier made 56 dollors more so 14w plus 56 equals 70w so kyle has 14w

step-by-step explanation: hope i plz give me brainliest with the points so this is not constant cause it says last week so its clearly not every week

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .