Problem situation:
Anna is at the movie theater and has $35 to spend.
She spends $9.50 on a ticket and wants to buy some snacks. Each snack costs $3.50.
How many snacks, , can Anna buy?

Inequality that represents this situation:
9.50+3.50≤35

Drag each number to show if it is a solution to both the inequality and the problem situation, to the inequality only, or if it is not a solution.

Step-by-step explanation:

Using x for the variable, the inequality will be ...

  9.50 +3.50x ≤ 35

  3.50x ≤ 25.50

  x ≤ 51/7 ≈ 7.3

Anna cannot buy negative snacks, and she cannot buy fractional snacks. Of the numbers listed, only 2 and 4 are integers between 0 and 7 (inclusive). The values below 7.3 are all solutions to the inequality. The value 9 1/2 is too large to be a solution to the inequality.

Only 2 and 4 are solutions to both the problem and the inequality.

9 1/2 is not a solution.

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

step-by-step explanation:

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