The function f(x) is a quartic function and the zeros of f(x) are -3,-1,4, and 6. Assume the leading coefficient of f(x) is 1. Write the equation of the quartic polynomial in standard form.

f(x) = x⁴-6x³-13x²+66x+72

Step-by-step explanation:

Factors are: (x+3)(x+1)(x-4)(x-6)

[(x+3)(x+1)][(x-4)(x-6)]

[x²+3x+x+3][x²-4x-6x+24]

(x²+4x+3)(x²-10x+24)

x⁴+4x³+3x²-10x³-40x²-30x+24x²+96x+72

f(x) = x⁴-6x³-13x²+66x+72

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!