Determine whether a triangle can be formed with the given side lengths. If so, use Heron's formula to find the area of the triangle. a = 240 b = 132 c = 330

240 + 132 > 330

132 + 330 > 240

330 + 240 > 132

Thus, it is possible to form a triangle with the sides a = 240, b = 132, c = 330.

s = (a + b + c)/2

s = (240 + 132 + 330)/2

s = 702/2

s = 351

A = s(s - a)(s - b)(s - c)

A = 351(351 - 240)(351 - 132)(351 - 330)

A = 351(111)(219)(21)

A = 179181639

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet