You may remember that the perimeter of a rectangle is P=2(W+L) where W is the width and L is the length. Suppose that the perimeter of a rectangle is 44 feet, and the length is 12 feet more than the width. Find the width of the rectangle, in feet.

The width of the rectangle is 5 feet.

Step-by-step explanation:

Let w represent the width of the rectangle.

The formula for determining the perimeter of a rectangle is expressed as

Perimeter = 2(W + L)

where W is the width and L is the length.

If the length of the rectangle is 12 feet more than the width, the expression would be

L = W + 12

Suppose that the perimeter of a rectangle is 44 feet, it means that

2(W + L) = 44

Dividing both sides of the equation by 2, it becomes

W + L = 22 - - - - - - - - - - - -1

Substituting L = W + 12 into equation 1, it becomes

W + W + 12 = 22

2W + 12 = 22

2W = 22 - 12 = 10

W = 10/2

W = 5

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6

14 ft 7 inches

step-by-step explanation:

since each model inch corresponds to 25 real inches, 7 model inches will correspond to

7×25" = 175"

at 12" per foot, that is 14 feet, 7 inches.