Professor Anthony calculated a chi-square statistic of 16.22 with df=8. What is the critical value of chi-square in order to test whether or not the outcome falls within the upper 1% of the distribution?

 The P-Value is .039337. The result is not significant at p < .01.

Step-by-step explanation:

In the following Chi square table attached, the value is of df=8 and chi square statistic value of 16.22 is found to be between (15.507, X²₀.₀₅) and    ( 17.353, X²₀.₀₂₅).

Using the table for critical value calculation:-

Df=8 Critical value for 1%= 1.646, and we calculated our value of 17.353.

We can reject is on the basis of X²calculated > X²Critical.

The outcome doesn't falls to be in 1% of the distribution.

or

We can reject it on basis that the outcome between X²₀.₀₅ and X²₀.₀₂₅ whereas the required level of upper distribution is X²₀.₀₁

do it yourself this is easy

step-by-step explanation:

given the equation is 8+9z=-6, the first step would be to subtract the 8 from both sides:

8+9z-8=-6-8

since 8 minus 8 = 0, this would cancel out the 8. and since -6 minus 8 equals -14, the equation would look like this

9z = -14