A) find center of mass of a solid of constant density bounded below by the paraboloid z=x^2+y^2 and above by the plane z=4.(b) Find the plane z=c that divides the solid into two parts of equal volume. This plane does not pass through the center of mass. The answers in the back of the book are:(a) x-bar=y-bar=z-bar=(8/3)(b) c=2(sqrt(2))

x-bar = y-bar = 0 whereas z-bar = 8/3

               M= (c^2)/8 which is intern equal to 2

Step-by-step explanation:

           Find the area, by setting the limits as

               =

Therefore;

Mxy=  

       z-bar = 8/3

M= 8 dividing it into two volume gives us = 4

means  

              c=2

true? is that what you're asking or do you mean something else?