What is the remainder when (3x3 – 2x2 4x – 3) is divided by (x2 3x 3)? 30 3x – 11 28x – 36 28x 30

The answer would be 28x+30.

You can do this by doing long division.

Refer to the attachment please.

The final quotient will then be 3x - 11 remainder 28x + 30

Option D is correct.

Step-by-step explanation:

Given:

Dividend = 3x³ - 2x² + 4x - 3

Divisor = x² + 3x + 3

To find: Remainder

We use Long Division Method (Synthetic Division Method)

Step  1 : we find first factor which we get 3x as 3x × x² = 3x³ the first term of dividend. Now, we multiply it with divisor and subtract from dividend.

Step  2: after subtraction we get -11x² - 5x - 3 as new dividend

Step 3 : Now we find 2nd factor which is -11 as -11 × x² = -11x². Now, we multiply it with divisor and subtract from new dividend

Step 4: After step 3 we get 28x + 30 , which is our required remainder

Therefore, Option D is correct .i.e., Remainder is 28x + 30

a_n = a_1 + (n - 1)d

the first term is 6.

the common difference d = ?

when you find d, replace n with 7 and d with the common difference to find your answer.