Records show that the average commute time for a person living in Atlanta in 2000 was 42 minutes. An analyst claims that the average commute time in 2007 was longer. The analyst takes a simple random sample of thirteen commuters in 2007 and calculates an average of 46.4 and a standard deviation of 3.8. (It is reasonable to assume that the population of commute times has a normal distribution.)

Which of the following is the appropriate test statistic?

t = (46.4 - 42.0)/(3.8/√13)

z = (42.0 - 46.4)/(3.8/√13)

z = (46.4 - 42.0)/(3.8/√13)

t = (42.0 - 46.4)/(3.8/√13)

None of the above

Option a)  t = (46.4 - 42.0)/(3.8/√13)

Step-by-step explanation:

Here we are given that Records show that the average commute time for a person living in Atlanta in 2000 was 42 minutes i.e. = 42

And to test this a sample of thirteen commuters in 2007 has been taken and calculates an average of 46.4 and a standard deviation of 3.8 i.e.;

Sample Mean, X bar = 46.4             Sample standard deviation,s = 3.8

Sample size, n = 13

Since, here we know nothing about population standard deviation so we will use t statistics here ;

  Test statistics =   ~

Therefore, appropriate test statistic = ~ .

the answer is; biodiversity resulting from few ancestors

adaptive radiation occurs when a population is subjected to a large natural environment with spatial ecological variations. the parts of the population in the different ecologies begin to adapt to their local environments. due to non-random mating across the large populations, this causes the different populations from the large population to speciate within their local environments. they, therefore, diverge to different species sharing a common ancestor.  

answer: i literally just answered this question but they want me to do it again

step-by-step explanation: