Three components are randomly sampled, one at a time, from a large lot. As each component is selected, it is tested. If it passes the test, a success (S) occurs; if it fails the test, a failure (F) occurs. Assume that 79% of the components in the lot will succeed in passing the test. Let X represent the number of successes among the three sampled components.
Find P(SFS) and P(SSF)

The probability of SFS and SSF are same, i.e. P (SFS) = P (SSF) = 0.1311.

Step-by-step explanation:

The probability of a component passing the test is, P (S) = 0.79.

The probability that a component fails the test is, P (F) = 1 - 0.79 = 0.21.

Three components are sampled.

Compute the probability of the test result as SFS as follows:

P (SFS) = P (S) × P (F) × P (S)

Compute the probability of the test result as SSF as follows:

P (SSF) = P (S) × P (S) × P (F)

Thus, the probability of SFS and SSF are same, i.e. P (SFS) = P (SSF) = 0.1311.

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let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.