Can someone please help (and show work plz)

  AX = 20

  AY = 15

Step-by-step explanation:

The perimeter is ...

  P = AC +CB +BA = (AX +XC) +CB +(BY +YA)

  128 = AX +32 + 37 +24 +AY

  35 = AX +AY

The ratios of corresponding sides are proportional:

  AX/AY = XC/YB = 32/24 = 4/3

This tells us ...

  AX = 4/3·AY

Substituting, we get ...

  35 = (4/3)AY +AY = (7/3)AY

  (3/7)·35 = 15 = AY

  AX = 35 -AY = 20

The side measures are AX = 20, AY = 15.

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

$4034.40

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40