Pls answer! I don’t know math @ all

The probability that the outcome is a sum that is a multiple of 6 or a sum that is a multiple of 4 is .

Solution:

Total number of outcomes N(S) = 36

Let A be the sum that is a multiple of 6 and

B be the sum that is a multiple of 4.

Sum that is a multiple of 6 = (1, 5), (2, 4), (3, 3), (4, 2), (5, 1), (6, 6)

N(A) = 6

Sum that is a multiple of 4 = (1, 3), (2, 2), (2, 6), (3, 1), (3, 5),

                                              (4, 4), (5, 3), (6, 2), (6, 6)

N(B) = 9

Probability that the outcome is a sum that is a multiple of 6 or a sum that is a multiple of 4:

                (Make the denominator same)

Hence the probability that the outcome is a sum that is a multiple of 6 or a sum that is a multiple of 4 is .

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1