Assume that there are about 400 students in your class. If every student is to be assigned a unique bit pattern, a. What is the minimum number of bits required to do this? b. How many more students can be admitted to the class without requiring additional bits for each student's unique bit pattern?

a. 256 bits and b. 56 students

Step-by-step explanation:

Bit is a combination of 0 and 1

each byte contains 8 bit, so each student need 8 bits to assigned him a unique pattern

Zeros and ones means binary

Therefore 2^n

= 2^8

=256 bits

(b)

The number of students that can be admitted without additionl bit will be:

= 256 - 200

= 56 students

y > 1/3x

y < = -x + 4

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