Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a diameter of 16 feet and a height of 18 feet. Container B has a diameter of 22 feet and a height of 15 feet. Container A is full of water and the water is pumped into Container B until Container A is empty. After the pumping is complete, what is the volume of water in Container B, to the nearest tenth of a cubic foot?

Step-by-step explanation:

We must first determine the volume of cylinder A and the volume of cylinder B

Now if the content of cylinder A passes to cylinder B, this means that the volume of water that was in cylinder A is equal to the volume of cylinder B since all the water in A passed to B

, therefore the volume of water in B is 5701.99 ft3, and the nearest tenth of cubic foot will then be 5702 ft3

the terms of a geometric sequence can be found by beginning with the first term and multiplying by the common ratio repeatedly. a recursive formula for a geometric sequence with common ratio r is given by an=ran−1 a n = r a n − 1 for n≥2 n ≥ 2 .

step-by-step explanation: