![-x^2 +8x -14 \geq 0\\ -(x^2-8x+14)\geq0\\ -(x^2-8x+16-2)\geq0\\ -((x-4)^2-2)\geq0\\ -(x-4)^2+2\geq0\\ -(x-4)^2\geq-2\\ (x-4)^2\leq2\\ x-4 \leq \sqrt2 \wedge x-4\geq-\sqrt2\\ x\leq 4+\sqrt2 \wedge x\geq4-\sqrt2\\ x\in[4-\sqrt2,4+\sqrt2]\\\\ x\in[4-\sqrt2,4+\sqrt2] \wedge x\in\mathbb{Z}\\ \boxed{x=\{3,4,5\}} ](/tpl/images/0185/0162/5ce0f.png)
Solve the equation for x∈z
-x² +8x -14 ≥ 0...
Answers: 1
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