![\sum [a_{n+1}-a_n]=\sum (2n+1)=\sum 2n+\sum 1](/tpl/images/0517/4820/41fe0.png)
![\sum [a_{n+1}-a_n]=n(n+1)+n=n^2+2n](/tpl/images/0517/4820/9747a.png)
![\sum [a_{n+1}-a_n]=a_{n+1}-a_1](/tpl/images/0517/4820/89700.png)
Write the series using summation notation
-2+1+6+13+22+......
Mathematics, 20.02.2020 17:04, SunsetPrincess
Write the series using summation notation
-2+1+6+13+22+...
Answers: 1
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