Mathematics, 20.02.2020 09:00, twistedhyperboles

URGENT PLEASE HELP ME
how do i figure out if these are actually right triangles using the pythagorean theorem (in all the drop down boxes is just yes or no)

URGENT PLEASE HELP ME how do i figure out if these are actually right triangles using the pythagorea

Answers: 3

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answered: zackmoore

The Pythagorean Theorem states that the two legs squared will equal the hypotenuse squared.

Pythagorean Theorem:

a^2+b^2=c^2

Since we are given the length of the two legs and the hypotenuse, if we plug in the values they are equal, they are right triangles.

The hypotenuse is the side opposite from the right angle, which will be the longest side.

Let's plug in the values.

Triangle 1

$a^2+b^2=c^2\\$

$9^2+12^2=225\\15^2=225$

So the first triangle is a right triangle.

Triangle 2

a^2+b^2=c^2

$6^2+8^2=100\\10^2=100$

So the second triangle is also a right triangle.

Triangle 3

a^2+b^2=c^2

$2^2+4^2=20\\6^2=36$

So the third triangle is not a right triangle.

Hope this helped,

chikafujiwara

キズナミュージック♪

answered: Guest

$w\geq 14$

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

$2l+2w\geq 40$

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

$2\times 6+2w\geq 40$

now, we can solve for w

$12+2w\geq 40$

subtract both sides by 12

$12+2w-12\geq 40-12$

$2w\geq 28$

divide both sides by 2

and we get

$w\geq 14$

so,

the smallest possible measurement of the width is 14 feet

answered: Guest

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf =

pf = 6,25 u

ver más en -

step-by-step explanation:

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URGENT PLEASE HELP ME
how do i figure out if these are actually right triangles using the pyth...