Geode shaped approximately like a cylinder. It has a height of 26 feet and a diametet of 5.6 feet. What is the volume of the geode, rounded to the nearest tenth?

640.47 ft³

Step-by-step explanation:

v = πr²h, r = d/2 = 5.6/2 = 2.8

v = 3.142 * 2.8² * 26

v = 640.47 ft³

640.38 ft^3.

Step-by-step explanation:

Volume of a cylinder, V = pi*r^2*h

r = radius of the cylinder

= (5.6 ft)/2

= 2.8 ft

h = height of the cylinder

= 26 ft

V = pi * (2.8)^2 * 26

= 640.38 ft^3.

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step-by-step explanation: