The area of a rectangle pool is 192 square meters. The lenght of the pool is 4 meters more than its width. Find the length and width.

Step-by-step explanation:

The length of the pool is 4 meters more than its width

Let x and (x + 4m) represent the width and length respectively

 x(x+4m) = 192 m^2

solving for x

x^2 + 4m - 192 m^2 = 0

factoring

(x+16)(x-12)=0           |OR x+=+%28-4+%2B-+28%29%2F%282%29+ using Quadratic Formula

(x+16)=0  tossing out negative solution for measure

(x-12)=0   x = 12m, the width.  The length is 16m   (12m+4m)  

length is 52 and width is 44

Step-by-step explanation: I divided 192 into 4 which equals 48but since it's a rectangle you would have to subtract 4 from 48 twice and add 4 to 48 twice.

48+4=52

48+4=52

48-4=44

48-4=44

y = i/2 xtnop + (3i/2 tnop+ 1)

step-by-step explanation:

the picture is the step by step explanation.