2 + 2x - 5 = 5(x + 3)
Plz explain or show how to solve plz

x = -6

Step-by-step explanation:

Simplifying

2 + 2x + -5 = 5[x + 3]

Reorder the terms:

2 + -5 + 2x = 5[x + 3]

Combine like terms: 2 + -5 = -3

-3 + 2x = 5[x + 3]

Reorder the terms:

-3 + 2x = 5[3 + x]

-3 + 2x = [3 * 5 + x * 5]

-3 + 2x = [15 + 5x]

Solving

-3 + 2x = 15 + 5x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-5x' to each side of the equation.

-3 + 2x + -5x = 15 + 5x + -5x

Combine like terms: 2x + -5x = -3x

-3 + -3x = 15 + 5x + -5x

Combine like terms: 5x + -5x = 0

-3 + -3x = 15 + 0

-3 + -3x = 15

Add '3' to each side of the equation.

-3 + 3 + -3x = 15 + 3

Combine like terms: -3 + 3 = 0

0 + -3x = 15 + 3

-3x = 15 + 3

Combine like terms: 15 + 3 = 18

-3x = 18

Divide each side by '-3'.

x = -6

⭐ Answered by Kakashi ʕ •㉨• ʔ⭐

⭐ Brainliest would be appreciated! ⭐

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∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

sorry

step-by-step explanation:

sorry, but im pretty sure its a now that i look at it