A school is designing two rectangular parking lots. The second parking lot is being designed so that its perimeter is 3/4 of perimeter of the first parking lot. Determine the Perimeter of the second parking lot.

The perimeter of second plot is 180 feet

Solution:

Given that,

The second parking lot is being designed so that its perimeter is 3/4 of perimeter of the first parking lot

Perimeter = 2(length + width)

From given figure in question,

length = 40 feet

width = 80 feet

Therefore,

Perimeter = 2(40 + 80)

Perimeter = 2(120) = 240

Thus, we got,

Perimeter of first parking plot = 240 feet

Also, given that,

Thus perimeter of second plot is 180 feet

step-by-step explanation:

the shape,the size and the distance

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .