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144.44 in² is the closest amount of paper she will use to wrap the gift.

Solution:

The given net is the shape of the cylinder.

Diameter of the circle = 4 in

Radius of the circle = 4 ÷ 2 = 2 in

Width of the container = 10.5 in

Length of the container is same as the circumference of the circle.

Area of the circle =

                             =

                             = 12.56 in²

Area of the 2 circles = 2 × 12.56 = 25.12 in²

Area of the rectangle = circumference × height

                                    =

                                    =

                                    = 131.88 in²

Area of the net of the container

                                   = Area of the circles + Area of the rectangle

                                   = 12.56 in² + 131.88 in²

                                   = 144.44 in²

Area of the net of the container =  144.44 in²

Hence  144.44 in² is the closest amount of paper she will use to wrap the gift.

2^y = ln 5, or   y(ln 2) = ln 5.   solving for y,   y = (ln 5) / (ln 2).   y=5

step-by-step explanation: