^ = squared
Factorise x^ + 4x - 12

The answer for the above problem is found to be "(x+6)X(x-2)"

Step-by-step explanation:

+ 4x - 12

= x^2 + 4x + 4 - 4 - 12

=x^2+ 4x + 4 - 16

=(x+2)^2 - 4^2

=(x+2+4)X(x+2-4)

=(x+6)X(x-2)

here is the explanations

since we have x^2, so we try to write the equation in (a+b)^2 = a^2 + 2ab + b^2 form.

to make it in square form we add 4 ( see at the second line). now we took 4 extra so we subtract 4 again.

in third line we have now x^2 + 4x + 4, this is perfect square in the form of (x+4)^2. next we took 16 as 4^2

in fourth line we apply (a+b)X(a-b) = a^2 - b^2 formula. here we took a = (x+4) and b= 4

then finally we get the answer as (x+6)X(x-2)

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)

ummm seems that u didnt post the attachement !